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10p^2-7p-7=0
a = 10; b = -7; c = -7;
Δ = b2-4ac
Δ = -72-4·10·(-7)
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{329}}{2*10}=\frac{7-\sqrt{329}}{20} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{329}}{2*10}=\frac{7+\sqrt{329}}{20} $
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